## [Coding] Minimum Number of Operations to Convert Time solution leetcode

You are given two strings`current`

and `correct`

representing two **24-hour times**. 24-hour times are formatted as

`"HH:MM"`

, where `HH`

is between `00`

and `23`

, and `MM`

is between `00`

and `59`

. The earliest 24-hour time is `00:00`

, and the latest is `23:59`

.
In one operation you can increase the time `current`

by `1`

, `5`

, `15`

, or `60`

minutes. You can perform this operation **any**number of times. Return

*the*

**minimum number of operations**needed to convert`current`

*to*

`correct`

.
### [Coding] Minimum Number of Operations to Convert Time solution leetcode

Input:current = "02:30", correct = "04:35"Output:3Explanation:We can convert current to correct in 3 operations as follows: - Add 60 minutes to current. current becomes "03:30". - Add 60 minutes to current. current becomes "04:30". - Add 5 minutes to current. current becomes "04:35". It can be proven that it is not possible to convert current to correct in fewer than 3 operations.

### [Coding] Minimum Number of Operations to Convert Time solution leetcode

Input:current = "11:00", correct = "11:01"Output:1Explanation:We only have to add one minute to current, so the minimum number of operations needed is 1.

### [Coding] Minimum Number of Operations to Convert Time solution leetcode

`current`

and`correct`

are in the format`"HH:MM"`

`current <= correct`

# ANSWER

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